Optimal. Leaf size=130 \[ -\frac{(3 a-2 b) (a+b) \sin (e+f x)}{3 a^2 b^2 f \sqrt{a+b \sin ^2(e+f x)}}+\frac{\tanh ^{-1}\left (\frac{\sqrt{b} \sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{b^{5/2} f}+\frac{(a+b) \sin (e+f x) \cos ^2(e+f x)}{3 a b f \left (a+b \sin ^2(e+f x)\right )^{3/2}} \]
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Rubi [A] time = 0.134544, antiderivative size = 130, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 5, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.2, Rules used = {3190, 413, 385, 217, 206} \[ -\frac{(3 a-2 b) (a+b) \sin (e+f x)}{3 a^2 b^2 f \sqrt{a+b \sin ^2(e+f x)}}+\frac{\tanh ^{-1}\left (\frac{\sqrt{b} \sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{b^{5/2} f}+\frac{(a+b) \sin (e+f x) \cos ^2(e+f x)}{3 a b f \left (a+b \sin ^2(e+f x)\right )^{3/2}} \]
Antiderivative was successfully verified.
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Rule 3190
Rule 413
Rule 385
Rule 217
Rule 206
Rubi steps
\begin{align*} \int \frac{\cos ^5(e+f x)}{\left (a+b \sin ^2(e+f x)\right )^{5/2}} \, dx &=\frac{\operatorname{Subst}\left (\int \frac{\left (1-x^2\right )^2}{\left (a+b x^2\right )^{5/2}} \, dx,x,\sin (e+f x)\right )}{f}\\ &=\frac{(a+b) \cos ^2(e+f x) \sin (e+f x)}{3 a b f \left (a+b \sin ^2(e+f x)\right )^{3/2}}+\frac{\operatorname{Subst}\left (\int \frac{-a+2 b+3 a x^2}{\left (a+b x^2\right )^{3/2}} \, dx,x,\sin (e+f x)\right )}{3 a b f}\\ &=\frac{(a+b) \cos ^2(e+f x) \sin (e+f x)}{3 a b f \left (a+b \sin ^2(e+f x)\right )^{3/2}}-\frac{(3 a-2 b) (a+b) \sin (e+f x)}{3 a^2 b^2 f \sqrt{a+b \sin ^2(e+f x)}}+\frac{\operatorname{Subst}\left (\int \frac{1}{\sqrt{a+b x^2}} \, dx,x,\sin (e+f x)\right )}{b^2 f}\\ &=\frac{(a+b) \cos ^2(e+f x) \sin (e+f x)}{3 a b f \left (a+b \sin ^2(e+f x)\right )^{3/2}}-\frac{(3 a-2 b) (a+b) \sin (e+f x)}{3 a^2 b^2 f \sqrt{a+b \sin ^2(e+f x)}}+\frac{\operatorname{Subst}\left (\int \frac{1}{1-b x^2} \, dx,x,\frac{\sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{b^2 f}\\ &=\frac{\tanh ^{-1}\left (\frac{\sqrt{b} \sin (e+f x)}{\sqrt{a+b \sin ^2(e+f x)}}\right )}{b^{5/2} f}+\frac{(a+b) \cos ^2(e+f x) \sin (e+f x)}{3 a b f \left (a+b \sin ^2(e+f x)\right )^{3/2}}-\frac{(3 a-2 b) (a+b) \sin (e+f x)}{3 a^2 b^2 f \sqrt{a+b \sin ^2(e+f x)}}\\ \end{align*}
Mathematica [A] time = 0.809614, size = 128, normalized size = 0.98 \[ \frac{\frac{2 \sqrt{2} (a+b) \sin (e+f x) \left (-3 a^2+b (2 a-b) \cos (2 (e+f x))+a b+b^2\right )}{a^2 (2 a-b \cos (2 (e+f x))+b)^{3/2}}+\frac{3 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{-b} \sin (e+f x)}{\sqrt{2 a-b \cos (2 (e+f x))+b}}\right )}{\sqrt{-b}}}{3 b^2 f} \]
Antiderivative was successfully verified.
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Maple [B] time = 3.361, size = 383, normalized size = 3. \begin{align*}{\frac{1}{3\,{a}^{2} \left ({b}^{2} \left ( \cos \left ( fx+e \right ) \right ) ^{4}-2\,ab \left ( \cos \left ( fx+e \right ) \right ) ^{2}-2\,{b}^{2} \left ( \cos \left ( fx+e \right ) \right ) ^{2}+{a}^{2}+2\,ab+{b}^{2} \right ) f} \left ( 3\,\ln \left ( \sin \left ( fx+e \right ) \sqrt{b}+\sqrt{a+b-b \left ( \cos \left ( fx+e \right ) \right ) ^{2}} \right ){a}^{4}{b}^{4}+6\,\ln \left ( \sin \left ( fx+e \right ) \sqrt{b}+\sqrt{a+b-b \left ( \cos \left ( fx+e \right ) \right ) ^{2}} \right ){a}^{3}{b}^{5}+3\,\ln \left ( \sin \left ( fx+e \right ) \sqrt{b}+\sqrt{a+b-b \left ( \cos \left ( fx+e \right ) \right ) ^{2}} \right ){a}^{2}{b}^{6}+3\,\ln \left ( \sin \left ( fx+e \right ) \sqrt{b}+\sqrt{a+b-b \left ( \cos \left ( fx+e \right ) \right ) ^{2}} \right ){a}^{2}{b}^{6} \left ( \cos \left ( fx+e \right ) \right ) ^{4}-6\,\ln \left ( \sin \left ( fx+e \right ) \sqrt{b}+\sqrt{a+b-b \left ( \cos \left ( fx+e \right ) \right ) ^{2}} \right ){a}^{2}{b}^{5} \left ( a+b \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{2}+2\,{b}^{11/2}\sqrt{-b \left ( \cos \left ( fx+e \right ) \right ) ^{2}+{\frac{a{b}^{2}+{b}^{3}}{{b}^{2}}}} \left ( 2\,{a}^{2}+ab-{b}^{2} \right ) \sin \left ( fx+e \right ) \left ( \cos \left ( fx+e \right ) \right ) ^{2}-\sin \left ( fx+e \right ){b}^{{\frac{9}{2}}}\sqrt{-b \left ( \cos \left ( fx+e \right ) \right ) ^{2}+{\frac{a{b}^{2}+{b}^{3}}{{b}^{2}}}} \left ( 3\,{a}^{3}+4\,{a}^{2}b-a{b}^{2}-2\,{b}^{3} \right ) \right ){b}^{-{\frac{13}{2}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 12.5564, size = 1828, normalized size = 14.06 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (f x + e\right )^{5}}{{\left (b \sin \left (f x + e\right )^{2} + a\right )}^{\frac{5}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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